 | James Thompson - 1808 - 176 pages
...area of a trafiezoid, or quadrangle, <u'o cf •whose opposite sides are parallel. RULE — Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product •will be the area. EXAMPLES. 13. Required the area of a trapezoid whose parallel... | |
 | Matthew Iley - 1820 - 512 pages
...an Inch in Depth, of a Quadrilateral having two Parallel unequal Sides. RULE. By the Pen. Multiply half the sum of the parallel sides by the perpendicular distance between them, and divide the product by the number of cubic inches in the proposed integer. By the Sliding Rule.... | |
 | Anthony Nesbit - 1824 - 476 pages
...is its area ? Ans. 1131^.2 in. 9 pa. PROBLEM VIII. To find the area of a Irapezoid. RULE. Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the area. Or, half the sum of the sides multiplied by their distance will... | |
 | William Galbraith - 1827 - 412 pages
...Trapezium. — Multiply the base into half the sum of the perpendiculars. 4. Trapezoid. — Multiply half the sum of the parallel sides by the perpendicular distance between them. 5. Irregular Polygon. — Divide it into triangles, find their areas, the sum of these will be the... | |
 | Thomas Hornby (land surveyor.) - 1827 - 318 pages
...00000000 2.40000 40 16.00000 Ans. 0A. 2n. 16p. PROBLEM 3. To find the Area of a Trapezoid. RULE. Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the area. EXAMPLE. Required the area of the trapezoid AB CD, whose parallel... | |
 | John Bonnycastle - 1829 - 256 pages
...the area of a trapezoid, or a quadrangle, two of whose opposite sides are parallel. RULE.* Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the EXAMPLES. 1. Required the area of the trapezoid ABCD, whose sides... | |
 | Edinburgh encyclopaedia - 1830 - 856 pages
...trapezoid is a quadrilateral, of which two opposite sides are parallel but not equal. RULE. Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product is the area. In the trapezoid ABCD, draw the diagonal AC, and from its extremities... | |
 | Francis Joseph Grund - 1834 - 212 pages
...triangles. 17. The areas of triangles, which have equal heights, are to each other, as their bases. 18. The area of a trapezoid is found by multiplying half the sum of the two parallel sides, by their distance. 19. The area of any rectilinear figure, terminated by any number... | |
 | William Galbraith - 1834 - 454 pages
...Trapezium. — Multiply the base into half the sum of the perpendiculars. 4. Trapezoid. — Multiply half the sum of the parallel sides by the perpendicular distance between them. fi. Irregular Polygon. — Divide it into triangles, find their areas, the sum of these will be the... | |
 | Robert Simson (master of Colebrooke house acad, Islington.) - 1838 - 206 pages
...^ 16s + 122 = 20, the length of the hypotenuse. HoW do you find the area of a trapezoid ? Multiply half the sum of the parallel sides by the perpendicular distance between them, and the product will be the area of the trapezoid. What is the area of a trapezoid, its parallel sides... | |
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Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the area. 
