 | 1853 - 266 pages
...the last $1230 ; what is the common difference ? Ans. $24. NOTE 5. — To find the number of terms, divide the difference of the extremes by the common difference, and add 1 to the quotient. EXAMPLES. 1 In a series, whose extremes are 4 and 1000, and the common difference 12, what is the number... | |
 | Benjamin Greenleaf - 1853 - 380 pages
...the sum of the extremes, and the product divided by 2, the quo tient would be the sum of the series. RULE. — Divide the difference of the extremes by the common difference, and add I to the quotient ; multiply this quotient by the sum of tht extremes, and half the product is the... | |
 | Daniel Leach - 1853 - 622 pages
...the basket? 314. To find the number of terms, when the extremes and common difference are known, — RULE. Divide the difference of the extremes by the common difference, and the quotient, increased by 1, will be the number of terms. This rule may be represented by the formulas,... | |
 | Benjamin Greenleaf - 1857 - 452 pages
...by 2, the quotient will be the sum of the series; therefore — i-? x 9 = 99, the answer required. RULE. — Divide the difference of the extremes by the common difference, and to the quotient add 1 ; by this sum multiply half the sum of the extremes, and the product will be... | |
 | Charles Guilford Burnham - 1857 - 342 pages
...When the first and last terms, and the common difference are given, to find the number of terms — RULE. Divide the difference of the extremes by the common difference, and the quotient will be 1 less than the number of terms. 10. If the first term of a series be 2, and the... | |
 | Charles Guilford Burnham - 1857 - 328 pages
...When the first and last terms, and the common difference* are given, to find the number of terms — RULE. Divide the difference of the extremes by the common difference, and the quotient will be 1 less than the number of terms. 10. If the first term of a series be 2, and the... | |
 | Benjamin Greenleaf - 1857 - 336 pages
...of differences ; therefore, 9 -j- 1 = 10 is the number of terms in this series. Hence the following RULE. — Divide the difference of the extremes by the common difference, and the quotient, increased by 1, will be the number of terms required. EXAMPLES FOR PRACTICE. 1. If the... | |
 | Benjamin Greenleaf - 1858 - 472 pages
...must be 1 more than the number of common differences, 8 -\1 = 9 is the number of terms in the series. RULE. — Divide the difference of the extremes by the common difference, and the quotient increased by 1 will be the required number of terms. EXAMPLES. 2. A man going a journey... | |
 | Horatio Nelson Robinson - 1859 - 362 pages
...term, we have left the common difference taken as many times as the number of terms, less 1. Hence, RULE. Divide the difference of the extremes by the common difference, and add 1 to the quotient. EXAMPLES. 1. The extremes are 7 and 43, and the common difference is 4 ; what is the number of terms... | |
 | Emerson Elbridge White - 1861 - 348 pages
...one. (3). The first term, common difference, and last term being given to find the number of terms. RULE. — Divide the difference of the extremes by the common difference, and add 1 to the quotient. (4). The first term, number of terms, and last term being given to find the sum of all the terms. RULE.... | |
| |
RULE. Divide the difference of the extremes by the common difference, and add 1 to the quotient. 
